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The value of αβ + βγ + γα, if α, β and γ are the zeros of 2x^3 – 4x^2 + 9x – 7 is _______(a) \(\frac {9}{2}\)(b) \(\frac {3}{2}\)(c) \(\frac {9}{8}\)(d) \(\frac {9}{5}\)The question was posed to me during an online exam.I need to ask this question from Zeros and Coefficients of Polynomial topic in division Polynomials of Mathematics – Class 10 |
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Answer» RIGHT answer is (a) \(\frac {9}{2}\) For EXPLANATION I WOULD say: β and γ are the zeros of 2x^3 – 4x^2 + 9x – 7 The sum of PRODUCT of TWO zeros or αβ + βγ + γα = \(\frac {coefficient \, of \, x}{coefficient \, of \, x^3} = \frac {9}{2}\) |
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