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The value of `Delta = |(1,1 + ac,1 +bc),(1,1 + ad,1 + bd),(1 ,1 + ae,1 + be)|`, isA. 1B. 0C. 3D. `a + b + c` |
Answer» Correct Answer - B We have, `Delta =|(1,1 + ac,1 +bc),(1,1 + ad,1 + bd),(1 ,1 + ac,1 + be)|` `rArr Delta = |(1,ac,bc),(1,ad,bd),(1,ae,be)|["Applying " C_(2) rarr C_(2) - C_(1),C_(3) rarr C_(3) - C_(1)]` `rArr Delta = ab |(1,c,c),(1,d,d),(1,e,e)| " " [("Taking a and b common from"),(C_(2) and C_(3) " respectively")]` `rArr Delta = 0` |
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