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The value of \(\dfrac{3^{502} - 3^{500} + 16}{3^{500} + 2}\) is1. 22. 43. 84. 16 |
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Answer» Correct Answer - Option 3 : 8 Given: Calculations: Dividing both the numerator and denominator by 3500 \(⇒ \dfrac{3^{2} - 1 + \dfrac{16}{3^{500}}}{1 + \dfrac{2}{3^{500}}}\) ∵ \( \dfrac{16}{3^{500}}\) and \( \dfrac{2}{3^{500}}\) are very very small and thus negligible. We can put 0 in their places \(⇒ \dfrac{3^{2} - 1}{1}\) ⇒ 9 - 1 ⇒ 8 ∴ The value of the given expression is 8 |
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