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The value of `((log)_2 24)/((log)_(96)2)-((log)_2 192)/((log)_(12)2)`is3 (b) 0(c) 2 (d) 1A. 3B. 0C. 2D. 1 |
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Answer» Correct Answer - A Let ` log_(2) 12 =a`, then ` 1/(log_(96)2) = log_(2) 96 = log_(2) 2^(3) xx 12 = 3 + a` ` log_(2) 24=1+a` ` rArr log_(2) 192 = log_(2) (16xx12) = 4 + a` ` and 1 /(log_(12)2) = log_(2) 12 = a` . Therefore, the given expression is: ` (1+a)(3+a)-(4+a) a = 3` |
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