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The value of the determinant `|(10!,11!,12!),(11!,12!,13!),(12!,13!,14!)|`, isA. `2(10! 11!)`B. `2(10! 13!)`C. `2(10! 11! 12!)`D. `2(11 ! 12! 13!)` |
Answer» Correct Answer - C We have, `|(10!,11!,12!),(11!,12!,13!),(12!,13!,14!)|` `= 10! xx 11! xx12! |(1,11,132),(1,12,156),(1,13,182)|` `= 10! xx 11! xx 12! |(1,11,132),(0,1,24),(0,1,26)|[("Applying " R_(2) rarr R_(2)- R_(1)),(" "R_(3) rarr R_(3) - R_(2))]` `= 2 (10! xx 11! xx 12!)` |
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