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InterviewSolution
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The values of `K_(p_(1))` and `K_(p_(2))` for the reactions `X hArr Y+Z` ….(i) and `A hArr 2B` …(ii) are in ratio of 9 : 1. If degree of dissociation of X and A be equal, then total presure at equilibrium (i) and (ii) are in the ratio.A. `3:1`B. `1:9`C. `36:1`D. `1:1` |
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Answer» Correct Answer - C Suppose the total pressure at equilibrium for the reactions (1) and (2) are `P_(1)` and `P_(2)` respectively. Then `{:(,X,hArr,Y,+,Z),("Initial",1 mol,,0,,0),("At eqm.",1-alpha,,alpha,,alpha):}` Total no. of moles at eqm. `=1+alpha` `P_(X)=(1-alpha)/(1+alpha)P_(1),P_(Y)=(alpha)/(1+alpha)P_(1),P_(Z)=(alpha)/(1+alpha)P_(1)` `K_(P)=(((a)/(1+a)P_(1))^(2))/(((1-a)/(1+a))P_(1))=(alpha^(2)P_(1))/(1-alpha^(2))=alpha^(2)P_(1)` `{:(,A,hArr,2B,),("At eqm.",1-alpha,,2alpha,):}` Total no. of moles at eqm. `=1+alpha` `P_(A)=(1-alpha)/(1+alpha)P_(2),P_(B)=(2alpha)/(1+alpha)P_(2)` `K_(p_(2))=(((2alpha)/(1+alpha)P_(2))^(2))/(((1-alpha)/(1+alpha))P_(2))=(4alpha^(2))/(1-alpha^(2))P_(2)~~P_(2)` `(K_(p_(1)))/(K_(p_(2)))=(alpha^(2)P_(1))/(4alpha^(2)P_(2))=(P_(1))/(4P_(2))=(9)/(1)`Given or `(P_(1))/(P_(2))=(36)/(1)` or ` P_(1) : P_(2) =36 :1` |
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