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The velocity-time graph of a linear motion os shown figure. The distance from the starting point after `8 sec` is. A. 5 mB. 16 mC. 8 mD. 19 m |
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Answer» Correct Answer - A Distance from the starting point is equal to displacement. Displacement = area of `v-t` graph =`(1)/(2)[4 + 2]4 - (1)/(2)[4 + 3] xx 2 = 5 m` Here distance travelled is not asked, but the distance from the the starting point. |
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