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The voltage applied to a pure capacitor of 50*10^-6 F is as shown in figure. Calculate the current for 0-1msec.(a) 5A(b) 1A(c) -5A(d) -1AThe question was asked in exam.Question is taken from Inductor and Capacitor topic in chapter Inductance, Capacitance, and Mutual Inductance of Electric Circuits

Answer»

The correct option is (a) 5A

Explanation: For 0≤t≤1msec,

V (t) =m*t (y=mx form)

→100= 1*10^-3*m →m= 1*10^5

→ V (t) = 1*10^5t

Current I (t) = c. d (v (t))/DT = 50*10^-6* (d (1*10^5t)/dt) = 5A.



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