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The voltage applied to the 212mH inductor is given by v(t)= 15e^-5tv. Calculate the current.(a) 16.782e^-10t(b) 15.75e^-5t(c) 11.27e^-10t(d) 14.15e^-5tI got this question during an interview.I'd like to ask this question from Inductor and Capacitor topic in chapter Inductance, Capacitance, and Mutual Inductance of Electric Circuits

Answer» CORRECT ANSWER is (d) 14.15e^-5t

The EXPLANATION: CURRENT I(t)= 1/L0∫tv*DT.


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