The zum of two numbers is 16 and sum of their reciprocals is 1/3. Find

1.	The zum of two numbers is 16 and sum of their reciprocals is 1/3. Find the numbers
Answer» Let one no. Is xthe other is 16-xAnd 1/x + 1/(16-x)=1/33(16-x)+3x=x(16-x)48-3x+3x=16x-x2x\u200b\u200b\u200b\u200b\u200b\u200b2\xa0-16x+48=0(x-12)(x-4)=0X=12,4So no. are 12 and 4 12 and 4 LET THE NUMBER BE X. AND Y. THE QUESTION SAYS THAT X+Y=16. AND THE OF THEIR RECIPROCAL IS 1/X+1/Y=1/3SO THE SECOND EQUATIO N IS. 3X+3Y=1

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