Theorem 10.1 and 10.2 solution

1.	Theorem 10.1 and 10.2 solution
Answer» Theorem no. 10.2In triangle PQO and PROOQ=OR (radius of same circle)Op=op (common)Angle Q = angleR (each 90)∆PQO conqurent ∆PROPQ=PR (cpct)

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