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Theorem 6.1 prove it please it is very important for me

Answer» Hiiii
Thank you ... Animesh for being sooo kind
Book mei dekho
And sorry diagram nhi bna skta
Given:-Tri. ABC where DE parallel BCTo proov:- AD/DB AE/ECProof :- area of tri. ADE= 1/2×base×height Area(Ade) =1/2×DB×EN Similarly area(BDE) = 1/2×DB×EN therefore area(ADE) =1/2×AD×EN/1/2×DB×EN=AD/DB - - - 1NOW, In tri. ADE and tri. DECArea(ADE) =1/2×AE×DMArea(DEC) =1/2×EC×DMTherefore, area(ADE)/area(DEC)=1/2×AE×DM/1/2×EC×DM=AE/EC - - - - - 2Tri.BDE and tri.DEC are on same base DE and between the same parallel BC and DE Area(BDE)=area(DEC) - - - 3Therefore, from equation 1,2 and 3 AD/DB=AE/EChence proved
Please .....tommorow is my maths exam


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