InterviewSolution
Saved Bookmarks
| 1. |
Theorem 6.1 prove it please it is very important for me |
|
Answer» Hiiii Thank you ... Animesh for being sooo kind Book mei dekho And sorry diagram nhi bna skta Given:-Tri. ABC where DE parallel BCTo proov:- AD/DB AE/ECProof :- area of tri. ADE= 1/2×base×height Area(Ade) =1/2×DB×EN Similarly area(BDE) = 1/2×DB×EN therefore area(ADE) =1/2×AD×EN/1/2×DB×EN=AD/DB - - - 1NOW, In tri. ADE and tri. DECArea(ADE) =1/2×AE×DMArea(DEC) =1/2×EC×DMTherefore, area(ADE)/area(DEC)=1/2×AE×DM/1/2×EC×DM=AE/EC - - - - - 2Tri.BDE and tri.DEC are on same base DE and between the same parallel BC and DE Area(BDE)=area(DEC) - - - 3Therefore, from equation 1,2 and 3 AD/DB=AE/EChence proved Please .....tommorow is my maths exam |
|