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There are two containers of equal capacity. The ratio of milk to water in the first container is 3 : 1, in the second container 5 : 2. If they are mixed up, the ratio of milk to water in the mixture will be1). 28 : 412). 41 : 283). 15 : 414). 41 : 15 |
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Answer» Let the volume of the two containers be V. Now, ? Milk to water ratio in the first container = 3 ? 1 ⇒ Volume covered by milk = 3V/4 and Volume covered by water = V/4 In the second container, milk to water ratio = 5 ? 2 ⇒ Amount of milk = 5V/7 and amount of water = 2V/7 When both the container’s content are MIXED, amount of milk = $(\frac{{3V}}{4} + \frac{{5V}}{7} = \frac{{21V + 20V}}{{28}} = \frac{{41V}}{{28}})$ And amount of water = $(\frac{V}{4} + \frac{{2V}}{7} = \frac{{7V + 8V}}{{28}} = \frac{{15V}}{{28}})$ Now, Ratio of milk to water in the new mixture = $(\frac{{\frac{{41V}}{{28}}}}{{\frac{{15V}}{{28}}}} = \frac{{41}}{{15}} = 41\;:15)$ |
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