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Three bottles of equal capacity have mixture of milk and water in ratio 5 : 7, 7 : 9 and 2 : 1 respectively. These three bottles are emptied into a large bottle. What is the percentage of milk in the new mixture?1). 49.62). 52.33). 51.24). 50.7 |
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Answer» Let the capacity of each bottle be y For bottle 1, milk be 5A and water be 7a ⇒ 5a + 7a = y ⇒ a = y/12…(i) For bottle 2, milk be 7b and water be 9b ⇒ 7b + 9b = y ⇒ b = y/16…(ii) For bottle 3, milk be 2C and water be c ⇒ 2c + c = y ⇒ c = y/3…(iii) ⇒ PERCENTAGE of milk can be given as = (5a + 7b + 2c) × 100/(5a + 7b + 2c + 7a + 9b + c) ⇒ Percentage of milk = (5a + 7b + 2c) × 100/(12a + 16b + 3c) …from (i), (ii) and (iii) ⇒ Percentage of milk = (5 × y/12 + 7 × y/16 + 2 × y/3) × 100/(y + y + y) ⇒ Percentage of milk = 50.7% ∴ the percentage of milk be 50.7% |
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