Three vertices of a parallelogram taken in order are (0,3) (0,6) and (2,9). Find the fourth vertex.

Three vertices of a parallelogram taken in order are (0,3) (0,6) and (

1.	Three vertices of a parallelogram taken in order are (0,3) (0,6) and (2,9). Find the fourth vertex.
Answer» 2,6 Let A(- 1, 0), B(3, 1), C(2, 2) and D(x, y) be the vertices of a parallelogram ABCD taken in order.Since, the diagonals of a parallelogram bisect each other.So, coordinate of the mid point of AC = coordinate of mid point of BD⇒ [(-1 + 2)/2, (0 + 2)/2] = [(3 + x)/2, (y + 1)/2]⇒ (1/2, 1) = [(3 + x)/2, (y + 1)/2](3 + x)/2 = ½ ⇒ x = - 2Also (y + 1)/2 = 1 ⇒ y + 1 = 2⇒ y = 1The fourth vertex of parallelogram = (- 2, 1). (2,6)