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To find the value of K if the points A(2,3) B(4,K) and C(6,-3) are collinear |
| Answer» If the points are collinear than there wold be no triangle formI. E area=01/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]=0\t[2(k+3)+4(-3-3)+6(3-k)=0\t2k+6-24+18-6k=0\t-4k=0\tk=0Hence for k=0 the points will be collinear. | |