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| 1. |
Triangle ABC smilir triangle PQR if AB by PQ=1BY 3 THEN FIND ar triangle ABC by ar triangle PQR |
| Answer» Given:\xa0{tex}\\Delta ABC \\sim \\Delta PQR{/tex}Since we know that ,the ratio of area of two similar triangles is equal to the square of ratio of their corresponding sides. Thus,{tex}\\frac{\\text { ar } \\triangle \\mathrm{ABC}}{\\text { ar } \\triangle \\mathrm{PQR}}{/tex}\xa0=\xa0{tex}\\frac{\\mathrm{AB}^{2}}{\\mathrm{PQ}^{2}}{/tex}\xa0=\xa0{tex}\\left(\\frac{1}{3}\\right)^{2}{/tex}\xa0=\xa0{tex}\\frac{1}{9}{/tex} | |