InterviewSolution
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InterviewSolution
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Trigonometry ratios |
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Answer» Sinθ=opposite/hypotenuseCosθ=adjacent/hypotenuseTanθ=opposite/adjacentCosecθ=hypotenuse/oppositeSecθ=hypotenuse/adjacentCotθ=adjacent/oppositeTanθ= Sinθ/CosθCosecθ=1/SinθSecθ=1/CosθCotθ=1/Tanθ sinA = p\\hcosA=b\\htanA=p\\bcosecA=h\\psecA=h\\bcotA=b\\p |
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