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two dices are thrown simultaneously ,find the probability of getting (i) an even number as the

Answer» According to the question,two dice are thrown simultaneously. We have to find the probability of getting an even number as the sum.Let A be the event of getting an even number as the sum i.e. 2, 4, 6, 8, 10, 12Elementary events favourable to event A are :(1, 1), (1, 3), (3, 1), (2, 2), (1, 5), (5, 1), (2, 4),(4, 2), (3, 3), (2, 6), (6, 2), (4, 4), (5,3) , (3,5),(5,5), (6,4), (4, 6) and (6, 6).Clearly, favourable number of elementary events = 18Hence, required probability{tex}= \\frac { 18 } { 36 } = \\frac { 1 } { 2 }{/tex}


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