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Two numbers differ by 3 and their product is 504.find the number

Answer» \xa0Let the first number be xAnd second number be x-3x(x-3)=504x2-3x-504=0x2-24x+21x-504=0x(x-24)+21(x-24)=0(x+21) (x-24)=0x=-21andx=24


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