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Two small discs of masses `m_1` and `m_2` interconnected by a weightless spring rest on a smooth horizontal plane. The discs are set in motion with initial velocities `v_1` and `v_2` whose directions are mutually perpendicular and lie in a horizontal plane. Find the total energy `overset~E` of this system in the frame of the centre of inertia. |
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Answer» As initially `U=overset~U=0`, so, `overset~E=overset~T` From the solution of `overset~T=1/2mu|vecv_1-vecv_2|`, As `vecv_1_|_vecv_2` Thus `overset~=1/2(m_1m_2)/(m_1+m_2)(v_1^2+v_2^2)` |
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