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Two spectral lines of sodium `D_(1) and D_(2)` have wavelengths of approximetely plane wave on to a slit of width `2 micrometer`. A screen is located `2m` from the slit. Find the spacing between the first maxima of two sodium lines as measured on the screen. |
Answer» Here, `lambda_(1) = 5890 Å = 5890 xx 10^(-10)m`, `a = 2 mu m = 2 xx 10^(-6)m` `lambda_(2) = 5896 Å = 5896 xx 10^(-10)m, D = 2 m` For the first secondary maxima, `sin theta = (3 lambda_(1))/(2 a) = (x_(1))/(D)` or `x_(1) = (3 lambda_(1) D)/(2 a) and x_(2) = (3 lambda_(2) D)/(2 a)` `:.` Spacing between the first secondary maxima of two sodium lines `= x_(2) - x_(1) = (3 D)/(2 a)(lambda_(2) - lambda_(1))` `= (3 xx 2(5896 - 5890) xx 10^(-10))/(2 xx 2 xx 10^(-6)) = 9 xx 10^(-4)m` |
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