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Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:

Answer» Let the speed of the slower train be x m/sec. Then, speed of the faster train = 2x m/sec. Relative speed = (x + 2x) m/sec = 3x m/sec. (100 + 100) = 3x 8 24x = 200 x = 25 . 3 So, speed of the faster train = 50 m/sec 3    = 50 x 18 km/hr 3 5    = 60 km/hr.


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