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Using Cofactors of elements of second row, evaluate `Delta=|(5, 3, 8),( 2, 0, 1),( 1, 2 ,3)|` |
Answer» Here, `A = |[5,3,8],[2,0,1],[1,2,3]|` First we will find minor of second row. `M_21 = 9-16 = -7` `M_22 = 15-8 = 7` `M_23 = 10-3 = 7` Now, we will find the cofactors using these minors. `A_21 = (-1)^(2+1)M_21 = -1(-7) = 7` `A_22 = (-1)^(2+2)M_22 = 1(7) = 7` `A_23 = (-1)^(2+3)M_23 = -1(7) = -7` Now, `a_21 = 2` `a_22 = 0` `a_23 =1` `:. Delta = a_21A_21+a_22A_22+a_23A_23` `=>Delta = 2(7)+0(7)+1(-7) = 14+0-7 = 7` `:. Delta = 7.` |
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