Saved Bookmarks
| 1. |
Using ecluid method find hcf of 210 and 55 |
| Answer» 210 = 55\xa0× 3 + 45 55 = 45\xa0× 1 + 1045 = 10\xa0× 4 + 510 = 5\xa0× 2 + 0HCF(55, 210) = 5 | |