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Using prime factorisation find the hcf and lcm of:24,36,40 |
| Answer» {tex}\\begin{array}{l}\\text{24=8×3=2}^3\\times3\\\\\\end{array}{/tex}{tex}\\begin{array}{l}\\text{36=4×9=2}^2\\times3^2\\\\\\end{array}{/tex}{tex} \\begin{array}{l}\\text{40=8×5=2}^3\\times5\\\\\\end{array}{/tex}Therefore, HCF = Product of the smallest power of each common prime factor in the numbers = 22 = 4Therefore, LCM = Product of the greatest power of each prime factor involved in the numbers {tex} \\begin{array}{l}=2^3\\times3^2\\times5=8\\times9\\times5=360\\\\\\end{array}{/tex} | |