Using prime factorization method find the hcf and LCM=product of 3 num

1.	Using prime factorization method find the hcf and LCM=product of 3 numbers???
Answer» The prime factors of:378 = 2 {tex} \\times{/tex}\xa033\xa0{tex}\\times{/tex} 7180 = 23\xa0{tex}\\times{/tex} 32\xa0{tex}\\times{/tex} 5420 = 22\xa0{tex}\\times{/tex} 3 {tex}\\times{/tex} 7{tex}\\times{/tex} 5HCF = 2 {tex}\\times{/tex} 3=6and LCM(378, 180, 420) = 22\xa0{tex}\\times{/tex} 33\xa0{tex}\\times{/tex} 5 {tex}\\times{/tex} 7 = 3780HCF {tex}\\times{/tex} LCM = 6 {tex}\\times{/tex} 3780 = 22680Product of given numbers is = 378 {tex}\\times{/tex} 180 {tex}\\times{/tex} 420 = 28576800Hence, HCF\xa0{tex}\\times{/tex}\xa0LCM {tex}\\ne{/tex}\xa0Product of three numbers.

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