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Using the property of determinants and without expanding, prove that:`|[0,a,-b],[-a,0,-c],[ b, c,0]|=0` |
Answer» `D= |[0,a,-b],[-a,0,-c],[b,c,0]|` We know, if we interchange rows and columns of a determinant, value of the determinant does not change. So, if we interchange rows and columns of given determinant, then, `D = |[0,-a,b],[a,0,c],[-b,-c,0]| = (-1)^3|[0,a,-b],[-a,0,-c],[b,c,0]| = -D` `:. D = -D` `=>2D = 0` `=> D = 0` Therefore, value of the given determinant is `0`. |
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