1.

Water flows through a rubber hose 2 cm in diameter at a velocity of 4 m/s. What must be the diameter of the nozzle in order that the water emerge at 16 m/s?(a) 0.884 cm(b) 0.891 cm(c) 0.881 cm(d) 0.894 cmI got this question by my college director while I was bunking the class.The question is from Fluids in Motion in portion Fluid Flow and Mixing of Bioprocess Engineering

Answer»

The correct option is (d) 0.894 cm

To ELABORATE: The area is PROPORTIONAL to the square of diameter, so:

v1d1^2 = v2d2^2

d2^2 = v1d1^2 / V2 = \(\frac{(4 \frac{m}{s})(2cm)^2}{(20 cm)^2}\)

d2 = 0.894 cm



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