1.

Water flows through a rubber hose 2 cm in diameter at a velocity of 4 m/s. What is the rate of flow rate of flow in m^3/min?(a) 0.0754 m^3/min(b) 0.0750 m^3/min(c) 0.0764 m^3/min(d) 0.0760 m^3/minThis question was posed to me in examination.The origin of the question is Fluids in Motion topic in section Fluid Flow and Mixing of Bioprocess Engineering

Answer» RIGHT OPTION is (a) 0.0754 m^3/min

For EXPLANATION: R = v1A1 = v2A2

R = v1A1; A1 = \(\frac{\pi d_2^1}{4}\)

R1 = v1 \(\frac{\pi d_2^1}{4} = \frac{(4 \frac{m}{s})\pi(0.02 m)^2}{4}\)

R1 = 0.00126 m^3/s

R1 = \(0.00126 \frac{m^3}{min} (\frac{1 min}{60 s})\)

R1 = 0.0754 m^3/min.


Discussion

No Comment Found

Related InterviewSolutions