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| 1. |
Water in canal |
| Answer» Consider an area of cross section of canal ABCD.Area of cross section =\xa0{tex}6 \\times 1.5{/tex}= 9Speed of water= 10 km/h =\xa0{tex}\\frac { 10000 } { 60 }{/tex}\xa0meter/minVolume of water that flows in 1 minute from canal =\xa0{tex}9 \\times \\frac { 10000 } { 60 } = 1500 \\mathrm { m } ^ { 3 }{/tex}Volume of water that flows in 30 minutes from canal =\xa0{tex}30 \\times 1500{/tex}= 45000 m3Let irrigated area be A.Volume of water irrigate in the required area will be equal to the volume of water flowed in 10 minutes from canal.Volume of water that flows in 30 minutes from canal = Volume of water irrigated in the required area{tex}45000 = \\frac { A \\times 8 } { 100 }{/tex}A = 562500 m2So, Area irrigated in 30 minutes is 562500 m2 | |