Water is pumped from a storage tank through a tube of 3.0 cm inside diameter at the rate of 0.001 m^3 /s. What is the kinetic energy per kg water in the tube?(a) 2.00 J/kg(b) 1.00 J/kg(c) 5.00 J/kg(d) 0.05 J/kgThis question was posed to me during an internship interview.The above asked question is from Energy Balance Numericals Without Reactions topic in chapter Energy Balance of Bioprocess Engineering

Water is pumped from a storage tank through a tube of 3.0 cm inside di

1.	Water is pumped from a storage tank through a tube of 3.0 cm inside diameter at the rate of 0.001 m^3 /s. What is the kinetic energy per kg water in the tube?(a) 2.00 J/kg(b) 1.00 J/kg(c) 5.00 J/kg(d) 0.05 J/kgThis question was posed to me during an internship interview.The above asked question is from Energy Balance Numericals Without Reactions topic in chapter Energy Balance of Bioprocess Engineering
Answer» The correct option is (b) 1.00 J/kg To explain I would say: Kinetic energy Ek =mv^2, tube dia. D = 3.0 CM, m = 1 kg. Cross-section area of tube A = \(\FRAC{1}{4}\) πD^2 = \(\frac{1}{4}\) π(3.0/100 m)^2 = 7.0686×10^-4m^2 Average velocity of water v = Q/A = 0.001 m^3 /(7.0686×10^-4m^2) = 1.415 m/s KE PER kg = Ek/m = 1/2 v^2 = 1/2 (1.415 m/s)^2 = 1.00 m^2/s^2 = 1.00 J/kg.

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