We need to find two consecutive odd integers, the sum of whose square

1.	We need to find two consecutive odd integers, the sum of whose square is 202
Answer» let the consecutive odd integers are x and x+2then x2+(x+2)2=202x2+x2+4x+4-202=02x2+4x-198=0x2+2x-99=0x2+11x-9x-99=0x(x+11)-9(x+11)=0(x+11)(x-9)=0x=-11,9So other no are -11+2 ad 9+2 or -9,11\xa0So the numbers are9,11 or -9,-11\xa0

Discussion