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What are the zeroes of quadratic polynomial x2+99x+127? |
| Answer» We need to find zeroes of x^2+99*x+127=0We have certainly got a formula for determining the zeroes of a 2 degree equation.That is called Discriminant formula or D- formula or Shri Dharacharya Method.Roots of the 2 degree equation are given by=(-b+(b^2-4*a*c)^(1/2))/2*a and (-b-(b^2-4*a*c)^(1/2))/2*a\xa0So, Zeroes of this equation is given by\xa0(-99+(99^2-4*1*127)^(1/2))/2*1 and (-99-(99^2-4*1*127)^(1/2))/2*1Hence,zeroes are -1.3 and -97.7 respectively. | |