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what current must flow if 0.24 coulombs is to be transferred in 15 ms |
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Answer» 1\xa0ms\xa0=\xa00.001sec15\xa0ms\xa0=\xa00.015secI\xa0=\xa0Q/TI = 0.24/0.015I =\xa016\xa0AmpereHence,\xa016\xa0Ampere\xa0will\xa0flow\xa0in\xa0the\xa0current. Hjgf jbh |
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