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| 1. |
What is cross multiplication |
| Answer» The below equation is solved by cross multiplication method:Given 5x + 4y - 4 = 0 .........(i)x - 12y - 20 = 0 ........(ii)Here, a\u200b\u200b\u200b\u200b\u200b\u200b1\u200b = 5, b1\u200b\u200b\u200b\u200b\u200b= 4, c\u200b\u200b\u200b1=\xa0-4a\u200b\u200b\u200b\u200b\u200b\u200b2\u200b= 1, b\u200b\u200b\u200b\u200b\u200b\u200b2\xa0= - 12, c\u200b\u200b2\xa0= - 40By cross-multiplication method,{tex}\\frac { x } { b _ { 2 } c _ { 1 } - b _ { 1 } c _ { 2 } } = \\frac { y } { c _ { 1 } a _ { 2 } - c _ { 2 } a _ { 1 } } = \\frac { 1 } { a _ { 1 } b _ { 2 } - a _ { 2 } b _ { 1 } }{/tex}{tex}\\frac { x } { - 80 - 48 } = \\frac { y } { - 4 + 100 } = \\frac { 1 } { - 60 - 4 }{/tex}{tex}\\frac { x } { - 128 } = \\frac { y } { 96 } = \\frac { 1 } { 64 }{/tex}{tex}\\frac { x } { - 128 } = \\frac { 1 } { - 64 } \\text { and } \\frac { y } { 96 } = \\frac { 1 } { - 64 }{/tex}Hence,\xa0{tex}x = 2 \\text { and } y = \\frac { - 3 } { 2 }{/tex} | |