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What is logarithm of ` 32 root(5) 4" to the base "2sqrt2`? |
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Answer» `log_(2sqrt2)32root(5)4=log_((2^(3//2)))(2^(5)4^(1/5))` ` = log_((2^(3//2)))(2^(5+2/5))` `=2/3 27/5 log_(2) 2` ` 18/5` ` = 3.6` |
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