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What is the altitude of an equilateral triangle of each side 6cm?

Answer» let ABC be an equilateral triangle and AD is the altitude from A to BC and BD=1/2 BC i.e. BD=3 cmThen in the\xa0right angled triangle\xa0ADB AB2 = BD2 +\xa0AD262\xa0= 32+ AD2AD=36 - 9= root\xa027= 3 root3 cm
Altitude of equilateral triangle=√3/2*side =√3/2*6 =3√3cm


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