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What is the angle between the plane of polariser and that of analyser to reduce the transmitted light intensity to half ? |
Answer» From Law of Malus, `I = I_(0) cos^(2)theta = (I_(0))/(2)` `:. Cos^(2) theta = (1)/(2) , cos theta = (1)/(sqrt(2)), theta = 45^(@)` |
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