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What is the bit storage capacity of a ROM with a 1024 × 8 organization?(a) 1024(b) 4096(c) 2048(d) 8192I have been asked this question during an internship interview.The doubt is from Programmable Read Only Memory topic in chapter Memory Devices of Digital Circuits

Answer»

Correct CHOICE is (d) 8192

For explanation I would say: For N ADDRESS bits, the memory location will CONSIST of 2^n bits. 1024 = 2^10. So, 2^10 * 2^3 = 1024 * 8 = 8192 bit.



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