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What is the formula used to find the zeros or roots of a quadratic polynomial

Answer» *Given a function of the form\xa0f(x)=ax2+bx+c, one can find the zeroes of the function (that is, where\xa0f(x)=0) by using\xa0the quadratic formula:\xa0x=−b±√b2−4ac2a.If the discriminant\xa0b2−4ac\xa0is less than zero, these roots will be complex or imaginary, and if the discriminant is greater than or equal to 0. these roots will be real.The use of\xa0±\xa0informs us that there are two solutions here; one where we are subtracting\xa0√b2−4ac, and one where we are adding it.*For a step by step example, assume the function\xa0f(x)=x2−7x+10. Here\xa0a=1,b=−7,c=10.\xa0If we set\xa0f(x)=0, then the values of x for which\xa0f(x)=0, that is to say the\xa0roots\xa0of\xa0f(x), would be determined by the quadratic formula:\xa0x=−(−7)±√(−7)2−4(1)(10)2(1)=7±√49−402=7±√92=7±32. Thus, our roots will be at\xa0x=7+32\xa0and\xa0x=7−32\xa0or\xa0x=5\xa0and\xa0x=2.On the graph of the function, we would see that the parabola crosses the x-axis at\xa0x=2\xa0and\xa0x=5.
First split the middle term and get factors of the given polynomial. Next to it put the factors equal to the value of zero. Then you will get the zeroes of the polynomial. You can also verify your answer using verification method.


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