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What is the molecule released in 2^nd step of Alk B reaction which returns the base to normal form?(a) Succinate(b) Alpha ketoglutarate(c) Formaldehyde(d) O2This question was addressed to me in class test.This interesting question is from Repair of DNA Damage: NER, Direct Reversal topic in portion DNA Mutation, DNA Repair, Transposable Elements of Cytogenetics

Answer» CORRECT answer is (C) Formaldehyde

Explanation: Alk B CONVERTS the METHYL group to carbonyl group by oxidation, with the help of alpha ketoglutarate. The 1^st step releases succinate while in the 2^nd step the carbonyl group releases the formaldehyde.


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