What is the probability of getting Aa Bb Cc from the cross aa BB cc X AA bb CC?(a) 1/4(b) 1/8(c) 1(d) 4The question was asked in an interview for job.I'm obligated to ask this question of Numerical Problems topic in division Mendelian Genetics of Cytogenetics

What is the probability of getting Aa Bb Cc from the cross aa BB cc X

1.	What is the probability of getting Aa Bb Cc from the cross aa BB cc X AA bb CC?(a) 1/4(b) 1/8(c) 1(d) 4The question was asked in an interview for job.I'm obligated to ask this question of Numerical Problems topic in division Mendelian Genetics of Cytogenetics
Answer» CORRECT answer is (c) 1 Best explanation: In this CASE, all three LOCUS is homozygous dominant for one and homozygous recessive for the other. Thus all the gametes are heterozygous. So considering the CALCULATION it will be 1 X 1 X 1 for A, B and C locus respectively.

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What is the probability of getting Aa Bb Cc from the cross aa BB cc X AA bb CC?(a) 1/4(b) 1/8(c) 1(d) 4The question was asked in an interview for job.I'm obligated to ask this question of Numerical Problems topic in division Mendelian Genetics of Cytogenetics

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