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What is the probability of getting factors of 3 when a die is rolled?(a) \(\frac {1}{3}\)(b) \(\frac {2}{3}\)(c) \(\frac {1}{6}\)(d) 0This question was posed to me in exam.Question is from Theoretical Approach to Probability topic in chapter Probability of Mathematics – Class 10

Answer»

Correct option is (a) \(\FRAC {1}{3}\)

To ELABORATE: Total number of outcomes are {1, 2, 3, 4, 5, 6} = 6

Factors of 3 in total outcomes are {3, 6} = 2

P(E) = \(\frac {Number \, of \, FAVORABLE \, outcomes}{Total \, number \, of \, outcomes}\)

= \(\frac {2}{6}\)

= \(\frac {1}{3}\)


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