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| 1. |
What is the smallest number when divided by 35,56 and 91 leaving a remainder 7 in each case |
| Answer» The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 9135 = 5 x 756 = 2 x 2 x 2 x 791 = 7 x 13LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647. | |