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What is the value of (1 + cotA)(1 + cotB) for isosceles right triangle ABC right angled at A?(a) 0(b) 1(c) 2(d) Data inadequateThe question was asked in an interview.My question comes from Trigonometric Equations topic in section Trigonometric Functions of Mathematics – Class 11

Answer»

The correct answer is (c) 2

The best explanation: (1 + COTA)(1 + cotB)

SIMPLIFYING the above EQUATION,

= 1 + cotA + cotB + cotAcotB

Putting the values of A and B, we get,

= 1 + cot90 + cot45 + cot90cot45

= 1 + 0 + 1 + 0

= 2.



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