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| 1. |
What is the value of cos square 67°-sin square23° |
| Answer» cos2 67° -\xa0sin2 23°= cos2\xa067°\xa0- sin2\xa0(90°- 67°)= cos2\xa067° - cos2\xa067° [since, sin(90o-a) = cos a]= 0 | |