What is the value of m is mx(x+7)49

1.	What is the value of m is mx(x+7)49
Answer» {tex}mx(x - 7) +49 = 0{/tex}\xa0{tex}\\Rightarrow{/tex}\xa0{tex}mx^2 - 7mx + 49 = 0{/tex}Here a = m, b = -7m, c = 49{tex}\\Rightarrow{/tex}\xa0{tex}D = b^2 - 4ac{/tex}For equal roots, D = 0{tex}\\Rightarrow{/tex}\xa00 = (-7m)2 - 4 {tex}\\times{/tex}\xa0m {tex}\\times{/tex}\xa049{tex}\\Rightarrow{/tex}\xa0{tex}0 = 49m^2 - 196m{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}49m^2 - 196m = 0{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}7m(7m - 28) = 0{/tex}{tex}\\Rightarrow{/tex}\xa07m = 0 or 7m - 28 = 0{tex}\\Rightarrow{/tex}\xa0m = 0 or m =\xa0{tex}\\frac{28}{7}{/tex}\xa0= 4but m\xa0{tex}\\ne{/tex}\xa00 [{tex}\\because{/tex}In quadratic a\xa0{tex}\\ne{/tex}\xa00]{tex}\\therefore{/tex}\xa0m = 4

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