What must be added to 6x^5+5x ^4+11x^3-3x^2+x+5 so that it may be exactly divisible by 3x^2-2x+4

What must be added to 6x^5+5x ^4+11x^3-3x^2+x+5 so that it may be exac

1.	What must be added to 6x^5+5x ^4+11x^3-3x^2+x+5 so that it may be exactly divisible by 3x^2-2x+4
Answer» Therefore, we must add -(-17x + 13) i.e. 17x - 13.