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| 1. |
What value of k 2 k - 7, k + 5 and 3 k + 2 are in AP |
| Answer» When 2k-7,k+5,3k+2 are in apd=3k+2-(k+5)=k+5-(2k-7)3k+2-k-5=k+5-2k+72k-3=-k+122k+k=12+33k=15K=5 | |